Comparison

Half Bridge vs Full Bridge Inverter

A 1 kVA online UPS converts 48 V DC battery to 230 V AC using an inverter stage — the choice between half-bridge and full-bridge topology determines how many IGBTs you need, whether you can reach that output voltage with your DC bus, and how much harmonic distortion the connected equipment must tolerate. Getting this choice wrong in a motor drive means either an undersized output or twice the component cost.

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Side-by-side comparison

ParameterHalf BridgeFull Bridge Inverter
Switch count2 switches (IGBTs or MOSFETs) — one high-side, one low-side4 switches — two legs, each with high and low side (H-bridge)
Output voltage amplitudeV_dc/2 — only half the DC bus availableV_dc — full DC bus voltage across load
DC bus capacitorTwo series capacitors required to create mid-point; each rated V_dc/2Single DC bus capacitor; no mid-point needed
Output waveform (single phase)Three-level: +V_dc/2, 0, –V_dc/2Three-level with PWM: +V_dc, 0, –V_dc (higher peak)
THD (with SPWM)Higher THD for same modulation index — lower output voltage headroomLower THD for same switching frequency — more effective volt-second control
Gate drive complexityOne isolated gate drive needed (for high-side switch)Two isolated high-side gate drives needed (one per leg)
Power rating suitabilityLow to medium power: up to ~5 kW (small UPS, auxiliary converters)Medium to high power: 1 kW to hundreds of kW (motor drives, solar inverters)
Shoot-through protectionSimpler — one pair of complementary switchesCritical — two legs; dead-time insertion needed per leg to prevent shoot-through
Common IC driverIR2110 (single bootstrap driver for one leg)IR2110 × 2 or IR2113 for both legs; gate drive transformer optional
Real applicationOff-line UPS auxiliary inverter, half-bridge LLC resonant converter in SMPSVFD for 3-phase induction motor (3 full-bridge legs), 1-phase grid-tied solar inverter

Key differences

The output voltage difference is decisive. A full-bridge inverter on a 400 V DC bus delivers ±400 V to the load, while a half-bridge delivers only ±200 V. For a 230 V AC RMS output you need a DC bus of at least 325 V peak — a half-bridge needs a 650 V bus while a full-bridge manages with a 325 V bus. That is why every commercial VFD for induction motors uses a full-bridge (three full-bridges for three phases, giving a 6-switch three-phase inverter). Half-bridges dominate in LLC resonant SMPS topologies where the symmetric switching halves voltage stress on the transformer primary. Dead-time between complementary gate signals — typically 0.5 μs to 2 μs — is mandatory in full-bridge to prevent shoot-through that would short the DC bus.

When to use Half Bridge

Use a half-bridge inverter when DC bus voltage is high enough to deliver the required output at half its value, or when component count must be minimal — a half-bridge LLC resonant converter in a 600 W PC power supply uses only two IGBTs with the DC bus split by two 470 μF capacitors.

When to use Full Bridge Inverter

Use a full-bridge inverter for motor drive or grid-tied inverter applications where maximum voltage utilisation from the DC bus is required — a 2.2 kW VFD for a three-phase induction motor uses three full-bridge legs driven by an IR2110-based gate drive circuit.

Recommendation

For power electronics exam problems, choose full-bridge whenever output power exceeds 1 kW or when the DC bus voltage is already near the minimum needed for the AC output. Half-bridge only makes sense when cost or switch count is explicitly constrained and the DC bus has sufficient headroom.

Exam tip: Examiners ask you to calculate the fundamental output voltage of a single-phase full-bridge SPWM inverter — know that V_1 = (4V_dc/π) × (M_a/2) for unipolar PWM where M_a is the modulation index, and state that full-bridge doubles the output compared to half-bridge for the same V_dc.

Interview tip: Interviewers at power electronics companies (Siemens, ABB, Delta hiring) ask you to explain dead-time and why it is critical in a full-bridge — answer that without dead-time, both switches in one leg conduct simultaneously for a few microseconds, shorting the DC bus and destroying the IGBTs, so a 1–2 μs delay is inserted between turn-off of one switch and turn-on of the other.

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