Short notes

AC Circuit Analysis Short Notes

When a 230 V, 50 Hz supply feeds a series RLC circuit with R = 10 Ω, L = 31.83 mH, and C = 318.3 μF, the circuit impedance is Z = R + j(ωL − 1/ωC) = 10 + j(10 − 10) = 10 Ω at the resonant frequency of 50 Hz — exactly resistive, with maximum current. Stepping slightly off resonance changes everything: the reactive part of Z reappears, current drops, and phase angle shifts. This sensitivity to frequency is why RLC circuits form the heart of filters, tuners, and impedance matching networks.

EEE, ECE, EI

How it works

In AC analysis, all voltages and currents are represented as phasors: V = V_m∠φ. Impedance Z = R + jX (Ω) where X = ωL for inductors and X = −1/ωC for capacitors. Admittance Y = 1/Z = G + jB. KVL and KCL apply unchanged to phasors: the only difference from DC analysis is that all quantities are complex numbers. Series resonance occurs at ω₀ = 1/√(LC), where |Z| is minimum and equals R. Parallel resonance occurs at the same ω₀ for ideal components, where |Z| is maximum. Quality factor Q = ω₀L/R = 1/(ω₀CR) for series RLC; bandwidth BW = ω₀/Q rad/s or f₀/Q Hz.

Key points to remember

At series resonance the voltage across L and across C individually can be Q times the source voltage — for Q = 10 and Vs = 10 V, VL = VC = 100 V. This voltage magnification is why series resonant circuits must be rated carefully. For parallel resonance, current in each branch can be Q times the supply current. The half-power frequencies are at ω₀ ± BW/2, where power drops to half the resonant value. Power factor = cos φ = R/|Z|; at resonance, PF = 1 and all source power is dissipated in R. Average power P = Vrms·Irms·cosφ; reactive power Q = Vrms·Irms·sinφ; apparent power S = Vrms·Irms.

Exam tip

The examiner always asks you to find the Q factor, bandwidth, and half-power frequencies of a given series RLC circuit — state Q = ω₀L/R, then BW = R/L rad/s, and half-power frequencies as ω₀ ± R/(2L) before plugging in numbers.

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