Short notes

Inverting Amplifier Short Notes

In a signal conditioning circuit for a pressure sensor, a μA741 inverting amplifier with R1 = 1 kΩ and Rf = 47 kΩ scales a 0–100 mV sensor output to 0–4.7 V for an ADC input — gain of −47, phase inverted. The inverting configuration is chosen here deliberately: input impedance is set by R1, which can be matched to the sensor's source impedance without loading it.

EEE, ECE, EI

How it works

The inverting amplifier applies the input signal Vin through R1 to the inverting (−) terminal; the non-inverting terminal is grounded; feedback resistor Rf connects output to the inverting input. Since the op-amp is ideal and has negative feedback, V− = V+ = 0 — the inverting terminal is a virtual ground. Current through R1: I1 = Vin/R1. Since no current enters the op-amp input, all of I1 flows through Rf: If = −Vout/Rf. Setting I1 = If gives Vout/Vin = −Rf/R1. Closed-loop gain ACL = −Rf/R1. Input impedance of the circuit is simply R1, not the op-amp's own Zin, because the virtual ground at the inverting terminal absorbs the input current. Output impedance is essentially zero due to the feedback. Bandwidth = GBW/|ACL|; for 741 GBW = 1 MHz, so gain of 10 gives bandwidth of 100 kHz.

Key points to remember

Closed-loop gain ACL = −Rf/R1; the negative sign indicates 180° phase inversion. Input impedance = R1 — not infinite, unlike the non-inverting configuration. Setting a compensating resistor R2 = R1 ∥ Rf at the non-inverting input minimises output offset due to bias currents; for R1 = 1 kΩ and Rf = 47 kΩ, R2 = 979 Ω ≈ 1 kΩ. Gain-bandwidth product is constant: for μA741, GBW = 1 MHz, so a gain of 100 gives bandwidth of only 10 kHz. To achieve gain of 1000 with flat response, a faster op-amp like the LM318 (GBW = 15 MHz) is needed. Gain error due to finite Aol: actual gain = −(Rf/R1)/(1 + (1+Rf/R1)/Aol), which approaches −Rf/R1 only when Aol >> 1 + Rf/R1.

Exam tip

Every VTU and Anna University paper asks you to derive the gain of an inverting amplifier using the virtual ground concept — state V− = 0, write KCL: Vin/R1 = −Vout/Rf, and conclude ACL = −Rf/R1 for guaranteed marks.

More Analog Electronics notes