Short notes

MOSFET Biasing Short Notes

Setting up a 2N7000 N-channel enhancement MOSFET as an audio amplifier requires biasing the gate to a voltage well above VTN = 2 V — typically 4–6 V — while keeping the drain voltage at roughly half VDD for maximum output swing. Because the gate draws zero DC current, biasing is simpler than BJT biasing, but the Q-point is still sensitive to the spread in VTN between devices from different batches.

EEE, ECE, EI

How it works

For enhancement MOSFETs, three biasing methods are common. Gate bias uses a voltage divider R1 and R2 to fix VGS directly: since IG = 0, no current flows through the divider into the gate, so VGS = VDD × R2/(R1+R2) exactly. This is stable against load changes but not against VTN variation between devices. Self-bias (drain-feedback bias) connects the gate directly to the drain: VGS = VDS, forcing the device into saturation automatically and providing negative feedback. Voltage divider with source resistor RS adds stability: VGS = VG − ID × RS, and if ID rises, VGS falls, reducing ID — the same feedback principle as BJT emitter degeneration. The Q-point is found by solving ID = (kn/2)(VGS − VTN)² simultaneously with the load line VDS = VDD − ID(RD + RS).

Key points to remember

Because gate current IG = 0, gate bias resistors can be in the megohm range (1 MΩ–10 MΩ) without loading the signal source — a major advantage over BJT biasing. Self-bias ensures VGS = VDS ≥ VGS − VTN only if VTN > 0, so it automatically guarantees saturation for enhancement MOSFETs. Q-point graphical solution requires drawing the bias line VGS = VG − ID × RS on the transfer characteristic curve ID vs VGS. Transconductance gm = 2ID/(VGS − VTN) at the Q-point must be calculated to find voltage gain AV = −gm × RD. Unlike BJTs, MOSFETs have no thermal runaway issue from VBE temperature dependence, but VTN still shifts with temperature (about −2 mV/°C).

Exam tip

The examiner always asks you to find the Q-point of a MOSFET voltage divider bias circuit — calculate VGS from the divider (remember IG = 0), then substitute into ID = (kn/2)(VGS − VTN)² and verify VDS = VDD − ID × RD.

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