Short notes

Transmission Lines EM Short Notes

A 50Ω coaxial cable connecting a 50Ω RF source to a 75Ω antenna has a reflection coefficient Γ = (75−50)/(75+50) = 0.2 at the load — 4% of incident power reflects back toward the source. That 4% reflected power is what causes VSWR of 1.5 on the line, and it's exactly why RF engineers obsess over impedance matching; in a 100W transmitter system, 4W returning to the PA can damage the output stage.

ECE

How it works

The transmission line equations give voltage and current as superposition of forward and reverse travelling waves: V(z) = V₊e^(−γz) + V₋e^(γz). For a lossless line, γ = jβ = j2π/λ. Characteristic impedance Z₀ = √(L/C) where L and C are per-unit-length inductance and capacitance. Reflection coefficient Γ_L = (Z_L − Z₀)/(Z_L + Z₀). Input impedance of a lossless line of length l: Z_in = Z₀[(Z_L + jZ₀tanβl)/(Z₀ + jZ_Ltanβl)]. For a quarter-wave transformer (l = λ/4), Z_in = Z₀²/Z_L — this is the impedance inverter property.

Key points to remember

VSWR = (1 + |Γ|)/(1 − |Γ|); for Γ=0 (matched), VSWR=1; for |Γ|=1 (open or short), VSWR=∞. A short-circuited quarter-wave stub acts as an open circuit at its terminals; an open-circuited quarter-wave stub acts as a short circuit. The Smith chart plots normalised impedance z = Z/Z₀ = r + jx as a point within the unit circle; moving along the chart circumference corresponds to moving along the transmission line. Single-stub matching uses a shunt stub to cancel the susceptance at a point where the normalised conductance is 1. Power delivered to load P = ½|V₊|²(1−|Γ|²)/Z₀.

Exam tip

The examiner always asks you to find VSWR, reflection coefficient, and input impedance for a given load and line length — compute Γ from load and Z₀ first, then use the input impedance formula, not the other way around.

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