Short notes

LVDT Short Notes

The linear variable differential transformer (LVDT) inside a pneumatic valve position indicator uses a ferromagnetic core attached to the valve stem; as the stem moves ±10 mm, the LVDT output voltage swings from −3 V to +3 V, giving 0.3 V/mm sensitivity. That linear, contactless displacement measurement in a harsh industrial environment is exactly why the LVDT appears in every instrumentation question paper.

EEE, EI

How it works

The LVDT has one primary coil excited by 1–10 kHz AC (say, 5 Vrms at 5 kHz) and two secondary coils wound in series-opposition. When the core is centred, mutual inductance to both secondaries is equal, so their induced voltages cancel and Vout = 0 V. Moving the core by +x increases coupling to S1 and decreases it to S2, producing a net output V1 − V2 that is proportional to displacement and in phase with the primary. Moving to −x gives the same magnitude but opposite phase. A phase-sensitive demodulator distinguishes direction by comparing output phase with the primary reference.

Key points to remember

LVDT characteristics: infinite resolution (no contact, no friction), excellent repeatability (< 0.1% FS), linearity within ±0.25% over the calibrated range (typically ±5 mm to ±250 mm depending on model). Operating frequency must be at least 10× the highest frequency of the measured displacement to avoid dynamic errors. The null voltage is never exactly zero due to residual quadrature voltage — this is a favourite examiner concept. Temperature affects sensitivity because coil resistance changes; LVDT signal conditioners like AD598 provide ratiometric output that cancels excitation amplitude variation.

Exam tip

The examiner always asks why LVDT output is never exactly zero at null position — explain that residual quadrature voltage (90° out of phase with primary) is due to winding capacitance and imperfect magnetic symmetry.

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