Short notes

Optoelectronics Short Notes

The red LED in a 7-segment display on a digital multimeter emits at 660 nm because AlGaAs has a direct bandgap of about 1.88 eV at that alloy composition — photon energy hf = 1.88 eV maps directly to 660 nm by λ = hc/Eg. Change the material to InGaN and the bandgap shifts to 2.7–3.4 eV, moving emission into the blue and green range. This bandgap engineering is the foundation of all LED and laser diode technology, and explaining why silicon cannot be used for efficient LEDs (indirect bandgap) is a 2-mark question answered incorrectly by a surprising number of students.

ECE, EI

How it works

In a direct bandgap semiconductor (GaAs, InP, GaN), electrons at the conduction band minimum and holes at the valence band maximum have the same crystal momentum — radiative recombination requires only a photon, with no phonon involved. Silicon and germanium have indirect bandgaps; recombination requires a phonon to conserve momentum, making radiation probability ~10⁶× lower. A PIN photodetector reverse-biased at −5 V has a wide intrinsic (I) region that provides a large depletion volume for photon absorption and fast carrier sweep-out; BPW34 silicon PIN photodiode responds from 430–1100 nm. Solar cell open-circuit voltage Voc = (nkT/q)·ln(IL/I0+1); short-circuit current ISC scales with illumination intensity. Laser diodes achieve lasing above threshold current density by stimulated emission in a Fabry-Perot cavity formed by cleaved facets.

Key points to remember

External quantum efficiency of a high-quality InGaN blue LED is above 80% in 2024-era devices — this was unthinkable before the work that earned the 2014 Physics Nobel Prize. Photodiode responsivity R = Iph/P_opt (A/W); for a silicon photodiode at 850 nm, R ≈ 0.6 A/W. Solar cell fill factor FF = Pmax/(Voc·ISC), typically 0.7–0.85 for silicon cells. Threshold current density for a Fabry-Perot InGaAsP laser diode at 1310 nm is typically 1–2 kA/cm². The avalanche photodiode (APD, e.g., Hamamatsu S2384) provides internal gain through impact ionisation in a high reverse bias (typically 150–200 V), enabling detection of very weak signals at the cost of added noise (excess noise factor F(M) = kM + (1−k)(2−1/M)).

Exam tip

The examiner always asks you to explain why silicon is not used for LED fabrication — state that silicon has an indirect bandgap, so radiative recombination probability is very low because momentum conservation requires phonon participation, making quantum efficiency too poor for practical light emission.

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