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Second Order Critically Damped Response

Fastest non-oscillatory, repeated real poles.

Mohith N
Updated: 19 March 2026
12 min read

In second-order control systems, the nature of the transient response depends entirely on the damping ratio. The critically damped response occurs when the damping ratio equals exactly 1, producing the fastest possible return to steady state without any oscillation. This condition is highly desirable in precision systems where overshoot cannot be tolerated.

Second Order Critically Damped Responsetc(t)1.0Critically Dampedζ = 1No OvershootResponse ComparisonCritically Damped (ζ=1)Overdamped (ζ>1)Underdamped (ζ<1)Poles: s = -ωn (repeated) | Characteristic Eq: (s + ωn)² = 0
Figure 1: Step response comparison showing critically damped (zeta=1) achieves steady state fastest without overshoot

Core Concept Explanation

A standard second-order system is described by its transfer function in terms of natural frequency omega_n and damping ratio zeta. When zeta equals exactly 1, the characteristic equation has two identical real roots at s = -omega_n. This is the boundary condition between oscillatory and non-oscillatory behavior.

The physical interpretation is straightforward. In a mechanical spring-mass-damper system, critical damping means the damping coefficient is precisely the value needed to prevent oscillation while returning to equilibrium as fast as possible. Below this value, the system oscillates. Above this value, the system is slower but still non-oscillatory.

The repeated real poles at s = -omega_n are the mathematical signature of critical damping. Because both poles coincide, the inverse Laplace transform produces a response that includes a term multiplied by time t, specifically of the form (1 + omega_n * t) * e^(-omega_n * t). This t-multiplied exponential decays, but it initially rises before falling, which explains the shape of the critically damped curve.

Mathematical Expression

The standard second-order transfer function is given as C(s)/R(s) = omega_n^2 / (s^2 + 2*zeta*omega_n*s + omega_n^2). For zeta = 1, this becomes omega_n^2 / (s + omega_n)^2. For a unit step input where R(s) = 1/s, the output in time domain is derived using partial fractions and inverse Laplace transform.

The unit step response for critically damped condition is c(t) = 1 - e^(-omega_n * t) * (1 + omega_n * t) for t >= 0. There is no oscillation, no overshoot, and the response asymptotically approaches 1. The peak value is exactly 1 (the final value), never exceeding it.

The settling time for critically damped response using 2% criterion is approximately 5.8 / omega_n, which is longer than the underdamped case at optimal zeta near 0.7 but shorter than heavily overdamped systems. This tradeoff is why critical damping is considered the practical sweet spot in many control designs.

Practical Understanding

In galvanometers, electrical measuring instruments, and certain servo systems, critical damping is the preferred design target. An overshoot in a galvanometer would cause pointer oscillation, making readings unreliable. A critically damped galvanometer settles immediately to its final deflection without bouncing.

In electronic circuits, the damping ratio is set by choosing appropriate resistor values in RLC circuits. For a series RLC circuit, critical damping occurs when R = 2 * sqrt(L/C). Engineers use this condition to design circuits that charge or respond as quickly as possible without ringing.

It is important to note that in practice, achieving exact critical damping is difficult because component tolerances cause slight variation in zeta. Most real systems are designed slightly overdamped (zeta between 1 and 1.5) to ensure no overshoot even under parameter variation.

Example
Given:
omega_n = 4 rad/s, zeta = 1 (critically damped)

Why this formula applies:
At zeta = 1, poles are repeated at s = -omega_n, giving response c(t) = 1 - e^(-omega_n*t)(1 + omega_n*t)

Formula:
c(t) = 1 - e^(-omega_n * t) * (1 + omega_n * t)

Substitution:
At t = 1 s: c(1) = 1 - e^(-4*1) * (1 + 4*1)

Calculation:
e^(-4) = 0.01832
c(1) = 1 - 0.01832 * 5 = 1 - 0.0916 = 0.9084

Final Answer:
c(1) = 0.908 (90.8% of final value reached at t = 1 s)
Settling time (2%) = 5.8 / 4 = 1.45 s
Exam Tip: For GATE, remember that critically damped response has zeta = 1 and repeated poles at s = -omega_n. The response formula contains the term t*e^(-omega_n*t). Settling time for critical damping (5.8/omega_n) is greater than optimally damped (zeta = 0.707) systems. Never confuse critically damped with fastest possible response - underdamped at zeta=0.707 settles faster for the same omega_n.

Mechanism: Pole Location and Response Shape

Pole Locations and Response Mechanismσjωs = -ωn(repeated)Both poles coincide on real axisNo imaginary part = No oscillationtc(t)1.0No overshootMonotonic riseTime Responses-Plane (Pole Plot)Response Equationc(t) = 1 - e⁻ʷⁿᵗ(1 + ωnt)t-multiplied exponential termcauses initial slow rise
Figure 2: s-plane pole location (left) and resulting time response (right) for critically damped second-order system
  • Repeated poles at s = -omega_n on the real axis produce no oscillatory component because there is no imaginary part in the pole location.
  • The response equation c(t) = 1 - e^(-omega_n*t)(1 + omega_n*t) contains a t*e^(-omega_n*t) term that arises from the double pole, causing an initial slower rise compared to underdamped case.
  • As omega_n increases, the critically damped system responds faster since poles move further left in the s-plane, meaning faster exponential decay.
  • Percentage overshoot is exactly zero for critically damped and overdamped systems, while underdamped systems have positive overshoot that increases as zeta decreases below 1.
  • The condition zeta = 1 is the minimum damping that guarantees no overshoot, making it the design target for systems where overshoot is completely unacceptable.

Quick Revision

  • Critical damping: zeta = 1, repeated real poles at s = -omega_n, characteristic equation (s + omega_n)^2 = 0.
  • Step response: c(t) = 1 - e^(-omega_n*t)(1 + omega_n*t), no oscillation, no overshoot.
  • Settling time (2% criterion): approximately 5.8/omega_n, slower than optimally damped (zeta=0.707) but faster than heavily overdamped.
  • Physical analogy: galvanometer with critical resistance, series RLC with R = 2*sqrt(L/C).
  • Exam trap: critically damped is NOT the fastest settling response. Underdamped at zeta=0.707 settles faster despite having some overshoot.
  • Transfer function: C(s)/R(s) = omega_n^2 / (s + omega_n)^2 at critical damping.
  • Key identifier in GATE problems: if poles are equal and real (repeated), the system is critically damped regardless of pole magnitude.

Critically Damped Response Quiz

Test your knowledge of critically damped system behavior, repeated poles, and time-domain response form.

Question 1 of 3

Q1.A critically damped second-order system with wn = 5 rad/s has its poles located at: