First Order RC Circuits
Step response, source-free response.
A first order RC circuit is one of the most fundamental circuits in transient analysis. It consists of a resistor and capacitor connected in series or parallel, and its response to a sudden change in input voltage describes how energy is stored and released in the capacitor over time. Understanding this circuit forms the foundation for analyzing filters, timing circuits, and signal conditioning systems.
Core Concept Explanation
When a DC voltage is suddenly applied to an RC circuit, the capacitor does not charge instantly. It charges gradually through the resistor, and the rate of charging depends on the product of R and C. This product is called the time constant, denoted by τ (tau), and has units of seconds. At t = τ, the capacitor charges to approximately 63.2% of the final steady-state voltage.
The step response refers to the output of the circuit when a step input (sudden switch from 0 to Vs) is applied. The capacitor voltage rises exponentially from 0 toward Vs. Physically, when the voltage is first applied, the capacitor behaves like a short circuit. As charge accumulates, the voltage across it builds and the current decreases.
The source-free response (also called natural response) occurs when the circuit has initial energy stored in the capacitor and the source is removed. The capacitor then discharges through the resistor, and its voltage decays exponentially to zero. The shape of both responses is the same exponential function, just in opposite directions.
It takes approximately 5τ for the circuit to reach steady state. After 5 time constants, the transient dies out and the circuit behaves as if it has been in that state permanently. This is a practical rule used in timing and filter design.
Mathematical Expression
The governing differential equation for the RC circuit is derived by applying Kirchhoff's voltage law. For a series RC circuit with applied voltage Vs:
Vs = i(t)·R + Vc(t), where i(t) = C·dVc/dt
Substituting and rearranging gives the first-order ODE: RC·dVc/dt + Vc = Vs. The solution for the complete response is: Vc(t) = Vs + (V0 - Vs)·e^(-t/τ), where V0 is the initial capacitor voltage, τ = RC, and Vs is the final steady-state value. This formula covers both charging (V0 = 0) and discharging (Vs = 0) cases.
For current: i(t) = (Vs - V0)/R · e^(-t/τ). At t = 0, the current is maximum (Vs/R if initially uncharged). It decays exponentially as the capacitor charges and limits further current flow.
Practical Understanding
RC circuits are everywhere in practical electronics. A camera flash charges a capacitor through a resistor and discharges it quickly through the flash lamp. Touch sensors use the charging time of an RC circuit to detect finger proximity. Signal smoothing filters exploit the fact that a capacitor blocks sudden changes in voltage, effectively averaging out rapid fluctuations.
In digital systems, RC time constants determine how fast logic signals can transition. If the RC time constant is too large, signals rise too slowly and timing margins are violated. This is a key consideration in printed circuit board (PCB) design and signal integrity analysis.
Given:
R = 10 kΩ, C = 100 µF, Vs = 12 V, Initial Vc(0) = 0 V
Why this formula applies:
Capacitor charges from 0 to Vs through R, so step response applies.
Formula:
Vc(t) = Vs(1 - e^(-t/τ)) where τ = RC
Substitution:
τ = 10×10³ × 100×10⁻⁶ = 1 second
Vc(τ) = 12 × (1 - e^(-1)) = 12 × (1 - 0.368)
Calculation:
Vc(τ) = 12 × 0.632 = 7.584 V
At t = 5τ = 5s: Vc = 12 × (1 - e^(-5)) ≈ 12 × 0.9933 ≈ 11.92 V
Final Answer: Vc at t = 1s is 7.58 V (≈ 63.2% of 12 V). At t = 5s, circuit reaches near steady state at 11.92 V.Exam Tip: For GATE, remember that at t = τ, capacitor voltage is 63.2% of final value. At t = 5τ, the transient is considered over. Never confuse τ = RC (seconds) with frequency. Also, initial capacitor voltage cannot change instantaneously — Vc(0+) = Vc(0−).
RC Response Waveforms
- During charging, Vc rises exponentially from 0 to Vs with the curve steepest at t = 0 and flattening as Vc approaches Vs.
- During discharging, Vc falls exponentially from V0 to 0. The energy stored in the capacitor dissipates as heat in the resistor.
- At t = τ during charging, Vc = 0.632·Vs. At t = τ during discharging, Vc = 0.368·V0.
- The current waveform is the derivative of Vc multiplied by C. Current is maximum at t = 0 and decays exponentially for both charging and discharging.
- A larger R slows the charging rate (larger τ) but the final voltage is unchanged. A larger C also increases τ because more charge is needed to raise the voltage.
Quick Revision
- Time constant τ = RC. Units are seconds. Governs speed of transient response.
- Step response: Vc(t) = Vs(1 - e^(-t/τ)). Source-free response: Vc(t) = V0·e^(-t/τ).
- At t = τ: capacitor is 63.2% charged. At t = 5τ: steady state reached (99.3%).
- Complete response = Forced response + Natural response. Final value + (Initial - Final)·e^(-t/τ).
- Vc(0+) = Vc(0−): capacitor voltage cannot change instantaneously — this is the key initial condition rule.
- Exam trap: Do not confuse τ with the period of oscillation. RC circuits do not oscillate — they only show exponential rise or decay.
- Current at t = 0+ in charging: i = Vs/R. Current at steady state: i = 0 (capacitor fully charged blocks DC).
RC Circuit Response
Test your ability to derive and interpret step and source-free responses in first-order RC circuits.
Q1.A capacitor C = 100 uF is charged to 50 V and then connected at t = 0 to a resistor R = 10 kohm. What is the voltage across the capacitor at t = 1 s?
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