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Multistage Amplifiers

Cascaded CE stages, overall gain, loading effect.

Darshan N
Updated: 7 April 2026
11 min read

A single transistor stage rarely provides enough gain for a practical system. Multistage amplifiers cascade two or more amplifier stages to achieve higher gain, and they appear in every analog signal chain from microphone preamplifiers to oscilloscope front ends.

Two-Stage CE Amplifier (BC547, VCC = 12V)Stage 1 (CE)BC547RC1 = 4.7 kΩRE1 = 1 kΩR1 = 47 kΩR2 = 10 kΩAV1 ≈ -120CC10µFStage 2 (CE)BC547RC2 = 4.7 kΩRE2 = 1 kΩR1 = 47 kΩR2 = 10 kΩAV2 ≈ -80VINVOUTAV(total) = AV1 × AV2 = (-120) × (-80) = 9600Phase: 180° + 180° = 360° = 0° (non-inverting overall)
Figure 1: Two-stage common emitter amplifier. Each stage inverts, so the overall output is non-inverting. Total voltage gain = AV1 × AV2.

Core Concept

Cascading amplifier stages multiplies their voltage gains. If stage 1 has AV1 = -120 and stage 2 has AV2 = -80, the total voltage gain is AV = AV1 * AV2 = 9600. Two CE stages cascade to give a net non-inverting output since each stage shifts phase by 180°. This is called a two-stage CE cascade.

The critical issue in cascading is loading. When stage 2 is connected to stage 1, the input impedance of stage 2 appears in parallel with RC1 of stage 1. This reduces the effective load seen by stage 1 and lowers AV1 below the standalone value. The loaded gain of stage 1 must be calculated using the parallel combination of RC1 and Rin2.

AC coupling with capacitors (10 µF electrolytic) is used between stages to prevent the DC bias of stage 2 from being disturbed by stage 1. At the midband frequencies the capacitors are short circuits. An alternative is direct coupling (DC-coupled), used in differential amplifiers like the LM741 input stage, which extends the response to DC but requires careful bias design.

Key Equations

Overall voltage gain: AV = AV1 * AV2 * ... * AVn. In decibels: AV(dB) = AV1(dB) + AV2(dB) + ....

Loaded gain of stage 1: AV1_loaded = -gm1 * (RC1 || Rin2) where Rin2 = R1_2 || R2_2 || rπ2 is the input impedance of stage 2.

Overall bandwidth shrinks with cascading: fH_total = fH_single * sqrt(2^(1/n) - 1) where n is the number of identical stages.

For n identical stages: BW_n = BW_1 * sqrt(2^(1/n) - 1). For n=2, BW shrinks by factor 0.644. For n=3, by factor 0.510.

Example
Given:
  Two-stage CE amplifier, BC547 in each stage
  VCC = 12V, IC1 = IC2 = 1 mA, beta = 100, VT = 26 mV
  RC1 = RC2 = 4.7 kΩ
  Stage 2 bias: R1 = 47 kΩ, R2 = 10 kΩ

Why this formula:
  Find gm, rπ, then Rin2, then loaded AV1, then AV2, then total.

Step 1 - Small signal params (same for both stages):
  gm = IC/VT = 1 mA / 26 mV = 38.46 mA/V
  rπ = beta/gm = 100/0.03846 = 2600 Ω = 2.6 kΩ

Step 2 - Input impedance of stage 2:
  Rin2 = R1||R2||rπ = 47k||10k||2.6k
  47k||10k = (47*10)/(47+10) k = 470/57 k = 8.246 kΩ
  8.246k||2.6k = (8.246*2.6)/(8.246+2.6) k = 21.44/10.846 = 1.977 kΩ
  Rin2 ≈ 1.98 kΩ

Step 3 - Loaded effective load for stage 1:
  RL1_eff = RC1 || Rin2 = 4700 || 1977
          = (4700*1977)/(4700+1977) = 9291900/6677 = 1391.7 Ω ≈ 1.39 kΩ

Step 4 - AV1 (loaded):
  AV1 = -gm * RL1_eff = -38.46×10⁻³ * 1391.7 = -53.5

Step 5 - AV2 (unloaded, standalone):
  AV2 = -gm * RC2 = -38.46×10⁻³ * 4700 = -180.8

Step 6 - Total gain:
  AV_total = AV1 * AV2 = (-53.5) * (-180.8)

Calculation:
  AV_total = 9672.8 ≈ 9673

Final Answer:
  AV1 (loaded) = -53.5, AV2 = -180.8
  Total voltage gain = +9673 (non-inverting)
  In dB: 20*log10(9673) = 79.7 dB
Exam Tip: GATE often gives a two-stage amplifier and asks for total gain without stating whether loading is included. Always compute Rin of the second stage first, then find the effective RC1 as RC1 || Rin2 for the first stage gain. Using standalone AV1 = gm*RC1 (without loading) will overestimate the total gain significantly. For bandwidth, remember that n identical stages reduce bandwidth by the factor sqrt(2^(1/n) - 1).

Key Properties

  • Total voltage gain = product of individual stage gains. In dB, gains add.
  • Stage 2 input impedance loads stage 1: effective RC1 = RC1 || Rin2, reducing AV1.
  • Two CE stages: 180° + 180° = 360° total phase shift, so overall output is non-inverting.
  • Bandwidth decreases with each added stage. Two identical stages give BW = 0.644 * single-stage BW.
  • AC coupling between stages allows independent DC biasing of each stage.
  • DC coupling (direct coupling) extends response to 0 Hz but requires matched bias design, as used in LM741 input differential pair.
  • A Darlington pair is a special two-stage connection (CC + CE or CC + CC) providing current gain of beta^2.

Quick Revision

  • AV_total = AV1 * AV2. In dB: add individual gains.
  • Always account for loading: RL1_eff = RC1 || Rin2.
  • Two CE stages: overall non-inverting (360° phase).
  • Bandwidth shrinks: two identical stages give BW_2 = 0.644 * BW_1.
  • AC coupling: independent DC bias per stage; blocks DC shifts between stages.
  • DC coupling: extends to DC; used in op-amp input stages.
  • Darlington pair: effective beta = beta1 * beta2, very high input impedance.
  • Exam trap: Students calculate AV1 = -gm*RC1 using the full RC1 value, ignoring that Rin2 is in parallel with RC1. This overestimates total gain by 3-4 times in a typical circuit.

Multistage Cascade Analysis

Evaluate overall gain and bandwidth of cascaded systems.

Question 1 of 3

Q1.What is the overall voltage gain of multiple amplifier stages connected in cascade?