Series Clipper
Positive and negative series clippers, transfer characteristics.
A series clipper is a waveform shaping circuit that places a diode in series with the signal path to remove (clip) one half of the input waveform. Unlike a shunt clipper where the diode is in parallel with the output, in a series clipper the diode controls whether the signal passes through or is blocked entirely. Series clippers are fundamental building blocks in signal processing, waveform generation, and protection circuits.
Core Concept Explanation
Figure 1 demonstrates how the diode placement in series creates the characteristic clipping behavior where one half of the waveform is completely blocked.
In a positive series clipper, the diode is oriented so that it is forward biased during the positive half cycle of the input signal. When the input is positive, the diode conducts and the positive half cycle appears across RL at the output. When the input goes negative, the diode becomes reverse biased and no current flows through the series path, so the output voltage is zero (or approximately zero for an ideal diode).
In a negative series clipper, the diode orientation is reversed. The diode now conducts during the negative half cycle and blocks the positive half cycle. The output contains only the negative portion of the input waveform. The choice between positive and negative series clipping depends on which portion of the signal needs to be preserved or removed.
The transfer characteristic of a series clipper describes the relationship between input voltage (Vin) and output voltage (Vout). For an ideal positive series clipper: Vout = Vin when Vin > 0, and Vout = 0 when Vin ≤ 0. For a practical silicon diode, conduction begins at Vin > 0.7 V, so a small portion near the zero crossing is also clipped.
Mathematical Expression
For an ideal positive series clipper, the output is: Vout = Vin for Vin > 0 V, and Vout = 0 for Vin ≤ 0 V. For a practical diode with forward voltage drop Vf = 0.7 V: Vout = Vin − Vf for Vin > Vf, and Vout = 0 for Vin ≤ Vf. The peak output is therefore Vm − 0.7 V.
When a DC bias voltage is added in series with the diode, the clipping level shifts. If a positive bias VB is added in the diode branch, clipping begins at Vin = VB (for ideal diode). This allows the clipping level to be set at any desired voltage, which is useful in signal limiting and protection applications.
Practical Understanding
Series clippers are used in circuits where it is necessary to completely block one polarity of a signal rather than just limit its amplitude. They are found in AM demodulators, overvoltage protection circuits, and pulse shaping networks. The key difference from a shunt clipper is that in a shunt clipper, the diode shorts out the undesired portion, while in a series clipper, the diode opens the circuit for that portion.
A practical concern is that during the blocking phase, the diode is reverse biased and the reverse leakage current allows a very small residual voltage to appear across RL. For most applications this leakage is negligible, but in precision circuits, it must be accounted for. The maximum reverse voltage across the diode equals the peak input voltage Vm, which must be within the diode's reverse breakdown rating (PIV specification).
Given:
Positive series clipper with practical diode
Input Vin = 10 sin(ωt) V → Vm = 10 V
Diode forward voltage Vf = 0.7 V
RL = 1 kΩ
Why this formula applies:
Diode conducts only when Vin > Vf; output is reduced by diode drop.
Formula:
Vout = Vin - Vf (when Vin > Vf)
Vout = 0 (when Vin ≤ Vf)
Calculation:
Peak output voltage = Vm - Vf = 10 - 0.7 = 9.3 V
Clipping starts at Vin = 0.7 V (not exactly at 0 V)
Final Answer:
Positive half of output: peak = 9.3 V
Negative half: completely clipped (Vout = 0)
PIV across diode during blocking = 10 VExam Tip: In series clipper, the half cycle that forward biases the diode passes to output (minus Vf). In shunt clipper, the half cycle that forward biases the diode is short-circuited to ground. Confusing the two is a very common GATE mistake — always trace current path.
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Quick Revision
- Series clipper: diode in series with signal path — blocks one half cycle completely.
- Positive clipper: passes +ve half (Vout = Vin − Vf), blocks −ve half (Vout = 0).
- Negative clipper: reverses diode, passes −ve half, blocks +ve half.
- Transfer characteristic: Vout = Vin − Vf for forward-biased region; Vout = 0 otherwise.
- Peak output = Vm − 0.7 V (practical silicon diode); Vm (ideal diode).
- Adding DC bias VB shifts clipping level — output passes when Vin > VB + Vf.
- GATE trap: Series clipper passes the biased half; shunt clipper grounds the biased half — opposite actions.
Series Clipper Circuit
Control waveform transmission using series diode arrangements.
Q1.What is the operational state of the diode in a basic unbiased positive series clipper during the positive half-cycle of the input signal?
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